# Arithmetic - How To Solve Complex Division Problems

## Learn How To Solve Complex Division Problems

To learn the steps in dividing numbers, let's pick a complex problem with a remainder as part of the problem answer, and solve it step by step. Let's start with the example below:

## Divide Two Positive Integer Numbers

+10√+10207

10√10207

## The dividend 10207 is less than the divisor
10.

It can not be divided by the divisor.

## Divide dividend 10 by divisor 10.

The divisor divides evenly in to the dividend

which equals 10 ÷ 10 = 1.

Put the division result 1 on the answer line.

Subtract 1 x 10 = 10 from the dividend value
10.

The a remainder of the division is 10 - 10 = 0.

Math check: (10 × 1) + 0 = 10.

`1`

10√10207

-10

0

10√10207

-10

0

## The dividend 102 07 is less than the divisor
10.

It can not be divided.

Put a zero on the answer line and subtract zero from last remainder.

Next, add the current dividend value 2 to
the current remainder.

`10`

10√10207

-10

2

-0

10√10207

-10

2

-0

## Divide dividend 20 by divisor 10.

The divisor divides evenly in to the dividend

which equals 20 ÷ 10 = 2.

Put the division result 2 on the answer line.

Subtract 2 x 10 = 20 from the dividend value
20.

The a remainder of the division is 20 - 20 = 0.

Math check: (10 × 2) + 0 = 20.

`102`

10√10207

-10

-0

20

-20

0

10√10207

-10

-0

20

-20

0

## The dividend 10207 is less than the divisor
10.

It can not be divided.

Put a zero on the answer line and subtract zero from last remainder.

Next, append the current dividend value 7 to
the current remainder.

`1020`

10√10207

-10

2

-0

20

-20

7

-0

7

10√10207

-10

2

-0

20

-20

7

-0

7

This problem is much more complex for two reasons:

(1) it requires multiple division steps to find the solution.

(2) it can not be divided evenly.

The answer remainder is 7 or stated another way 1020 7/10 →

(Divisor times Quotient) + Remainder = Dividend →

(10 × 1020) + 7 = 10207